x^2+3x^2=17^2

Solution for x^2+3x^2=17^2 equation:

x^2+3x^2=17^2

We move all terms to the left:

x^2+3x^2-(17^2)=0

We add all the numbers together, and all the variables

4x^2-289=0

a = 4; b = 0; c = -289;
Δ = b2-4ac
Δ = 02-4·4·(-289)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-68}{2*4}=\frac{-68}{8}
=-8+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+68}{2*4}=\frac{68}{8}
=8+1/2
$